cool sed/grep magic to convert output to csv format

2019-03-11 1 min read Bash Learning

I generallly keep doing this a lot, so thought will share with you. Lets assume we are capturing free ouput every min/hour/or whatever. The output looks like this:

Time: Mon Jan 21 23:59:10 AEDT 2019
——————-

total        used        free      shared  buff/cache   available
Mem:          32014        8656        1735        1697       21621       21308
Swap: 51195 75 51120

then we can use some grep and sed to convert this to something like this:

Mon Jan 21 23:59:10 AEDT 2019,32014,8656,1735,1697,21621,21308

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Directories with maximum number of files

2018-12-10 1 min read Bash

Lot of times, I want to find the directories with maximum number of files and so I wrote this quick function to do exactly the same

 

function count_lines ()
{
    oldIFS=$IFS
    count=0
    IFS=$'\n'
    dir=${1:-.}
    cd $dir
    find . -type d |while read line
    do
        echo -n "$(find $line -type f |wc -l) $line"
        echo 
        printf "Directories :: %8d\r" $count >&2
        ((count++))
    done|sort -n
    IFS=$oldIFS
}   # ----------  end of function count_lines  ----------

mv command with progress

2018-03-19 1 min read Bash

When moving large files/directories, I would like to see the progress.

Idea for this is to use rsync with progress and remove source files. But that option does not remove the empty directories left behind so find command to delete that.

So, here is function for that:

mv-progress () 
{ 
    rsync -ah --progress --remove-source-files "$1" "$2";
    find "$1" -empty -delete
}

Highest disk usage of directory in subdirectories

2018-03-12 1 min read Bash

I find myself doing this lot of times so thought will share this with you all. Basically, once I want to clear out the directory, I first want to find out the sub-directory using the maximum disk space so I wrote a function for that and here it is:

 

disk_usage_dirs () 
{ 
    find . -maxdepth 1 -type d -not -name '.' | while read line; do
        du -s "$line";
    done | sort -n | tail -${1:-5}
}

Some other posts you might find useful on this :

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search for a port number

2017-09-11 1 min read Bash Linux

I find myself doing google everytime I want to search for port number mapping. So, here is a short script to do just that 🙂

#!/bin/bash -
#===============================================================================
#
# FILE: portfind.sh
#
# USAGE: ./portfind.sh
#
# DESCRIPTION:
#
# OPTIONS: ---
# REQUIREMENTS: ---
# BUGS: ---
# NOTES: ---
# AUTHOR: Amit Agarwal (aka),
# ORGANIZATION:
# CREATED: 08/29/2017 19:00
# Last modified: Tue Aug 29, 2017 07:00PM
# REVISION: ---
#===============================================================================
set -o nounset # Treat unset variables as an error
#This is the directory where you have mappings file downloaded
ODIR=/root
ofile=$ODIR/service-names-port-numbers.xml

if [[ ! -f "$ofile" ]]
then
wget http://www.iana.org/assignments/service-names-port-numbers/service-names-port-numbers.xml -O "$ofile"
fi
which xmlstarlet >/dev/null 2>&1
if [[ $? == 0 ]]
then
echo "xmlstarlet is installed"
else
apt-get install xmlstarlet
fi

#### xmlstarlet el -u service-names-port-numbers.xml
## registry/record - protocol and number
proto=${2:-tcp}
port=${1:-21}
(echo '';sed '1,4d' $ofile) |xmlstarlet sel -t -m "//record[protocol='$proto'][number=$port]" -o "Number(Protocol): " -v number -o '(' -v protocol -o ')' -n -o "Description :" -v description -n
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